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Solved! Get answer or ask a different Question 4045

First, the graph of ##y=cos(x-pi/2)## will have some characteristics of the regular cosine function.
I also use a general form for trig functions: ##y = a cos(b ( x – c)) + d## where |a| = amplitude, ##2pi/|b|## = period, x = c is the horizontal phase shift, and d = vertical shift.

1) amplitude = 1 since there is no multiplier other than “1” in front of the cosine.

2) period = ##2pi## since the regular period of cosine is ##2pi##, and there is no multiplier other than a “1” attached to the x.

3) Solving ##x – pi/2=0## tells us that there is a phase shift (horizontal translation) of ##pi/2## to the right.

The bright, red graph is your graph!
Compare it to the dotted, blue graph of cosine. Do you recognize the changes itemized above?

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