##(a) ” ” 4.42″s”##

##(b)” ” 55.25″m”##

##(a)##

We get the time taken to reach the maximum height by using the vertical component of the velocity:

##v=u+at##

##:.0=25sin60-9.8t##

##:.t=61.65/9.8=2.21″s”##

By inference the return to earth will take the same time, assuming a level playing field.

##:. ## total time in flight ##=2xx2.21=4.42″s”##

##(b)##

The horizontal component of velocity is constant so we get:

Distance = speed x time

##=25cos60xx4.42=55.25″m”##